mechanics Module
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Lesson Directive // Gears & TorqueREF_CORE

Transmitting Motion

Ratio\text{Ratio}==NdrivenN_{\text{driven}}NdriverN_{\text{driver}}==ωdriver\omega_{\text{driver}}ωdriven\omega_{\text{driven}}

Hover over a variable in the formula above, or see glossary below:

Ratio\text{Ratio}
Gear Ratio
Unitless
NdrivenN_{\text{driven}}
Driven Gear Teeth
Count
NdriverN_{\text{driver}}
Driver Gear Teeth
Count
ωdriver\omega_{\text{driver}}
Driver Speed
RPM or rad/s
ωdriven\omega_{\text{driven}}
Driven Speed
RPM or rad/s

Gears are used to transmit rotational motion and torque between shafts. When two gears mesh, they rotate in opposite directions.

INSIGHT: Gears allow us to trade speed for torque, or torque for speed.

Calculating the Ratio

The gear ratio is found by dividing the number of teeth on the driven gear by the number of teeth on the driver gear.

INSIGHT: A ratio > 1 means the output is slower but has more torque.

Speed vs. Torque

If a small gear drives a large gear, the large gear turns slower but can provide a much stronger twisting force (torque).

INSIGHT: Speed and torque are inversely related in a gear train.
Detailed Theory & ReferencesEXT_DOC

Kinematics of Gear Trains

A gear train is a mechanical system formed by mounting gears on a frame so the teeth of the gears engage. Gear trains are fundamental in mechanical engineering to transmit torque and adjust the rotational speed between an input power source and an output load.

The Gear Ratio

For two meshing gears (a driver and a driven gear), the fundamental kinematic relationship—assuming no slip between the teeth profiles—dictates that their pitch circles roll against each other without slipping. Therefore, their tangential velocities at the point of contact must be equal.

The gear ratio RR is defined by the inverse relationship between the number of teeth NN and the angular velocity ω\omega: R=ωinωout=NoutNinR = \frac{\omega_{\text{in}}}{\omega_{\text{out}}} = \frac{N_{\text{out}}}{N_{\text{in}}}

Torque Multiplication

By the principle of conservation of energy (power P=τωP = \tau \omega), the input power must equal the output power in an ideal, frictionless gear system: τinωin=τoutωout\tau_{\text{in}} \omega_{\text{in}} = \tau_{\text{out}} \omega_{\text{out}}

Substituting the gear ratio yields the torque multiplication equation: τout=τin(ωinωout)=τin(NoutNin)\tau_{\text{out}} = \tau_{\text{in}} \left( \frac{\omega_{\text{in}}}{\omega_{\text{out}}} \right) = \tau_{\text{in}} \left( \frac{N_{\text{out}}}{N_{\text{in}}} \right)

If Nout>NinN_{\text{out}} > N_{\text{in}}, the system is a speed reducer and a torque multiplier. This is critical in robotics and spacecraft mechanisms where electric motors operate at high speeds with low torque, but actuators require low speeds and high torque.

Reference: Shigley, J. E., & Mischke, C. R. (2014). Mechanical Engineering Design (10th ed.). McGraw-Hill.

References

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